Solve 9-x/2+2x-10/2=x

$$\frac { 9 - x } { 2 } + \frac { 2 x - 10 } { 2 } = x$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Divide each term of 2x-10 by 2 to get -5+x.

$$\frac{9-x}{2}-5+x=x$$

Divide each term of 9-x by 2 to get \frac{9}{2}-\frac{1}{2}x.

$$\frac{9}{2}-\frac{1}{2}x-5+x=x$$

Convert 5 to fraction \frac{10}{2}.

$$\frac{9}{2}-\frac{1}{2}x-\frac{10}{2}+x=x$$

Since \frac{9}{2} and \frac{10}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-10}{2}-\frac{1}{2}x+x=x$$

Subtract 10 from 9 to get -1.

$$-\frac{1}{2}-\frac{1}{2}x+x=x$$

Combine -\frac{1}{2}x and x to get \frac{1}{2}x.

$$-\frac{1}{2}+\frac{1}{2}x=x$$

Subtract x from both sides.

$$-\frac{1}{2}+\frac{1}{2}x-x=0$$

Combine \frac{1}{2}x and -x to get -\frac{1}{2}x.

$$-\frac{1}{2}-\frac{1}{2}x=0$$

Add \frac{1}{2} to both sides. Anything plus zero gives itself.

$$-\frac{1}{2}x=\frac{1}{2}$$

Multiply both sides by -2, the reciprocal of -\frac{1}{2}.

$$x=\frac{1}{2}\left(-2\right)$$

Multiply \frac{1}{2} and -2 to get \frac{-2}{2}.

$$x=\frac{-2}{2}$$

Divide -2 by 2 to get -1.

$$x=-1$$