Solve 9/6sqrt{2}=6/x

$$\frac { 9 } { 6 \sqrt { 2 } } = \frac { 6 } { x }$$

Solve for x

$$x=4\sqrt{2}\approx 5.656854249$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$\frac{1}{12}x\times 2^{\frac{1}{2}}\times 9=6$$

Multiply \frac{1}{12} and 9 to get \frac{9}{12}.

$$\frac{9}{12}x\times 2^{\frac{1}{2}}=6$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$\frac{3}{4}x\times 2^{\frac{1}{2}}=6$$

Reorder the terms.

$$\frac{3}{4}\sqrt{2}x=6$$

The equation is in standard form.

$$\frac{3\sqrt{2}}{4}x=6$$

Divide both sides by \frac{3}{4}\sqrt{2}.

$$\frac{4\times \frac{3\sqrt{2}}{4}x}{3\sqrt{2}}=\frac{4\times 6}{3\sqrt{2}}$$

Dividing by \frac{3}{4}\sqrt{2} undoes the multiplication by \frac{3}{4}\sqrt{2}.

$$x=\frac{4\times 6}{3\sqrt{2}}$$

Divide 6 by \frac{3}{4}\sqrt{2}.

$$x=4\sqrt{2}$$