Solve 9/4+15/4+33/4+63/4+frac{129}{4}=

$$\frac { 9 } { 4 } + \frac { 15 } { 4 } + \frac { 33 } { 4 } + \frac { 63 } { 4 } + \frac { 129 } { 4 } =$$

Evaluate

$$\frac{249}{4}=62.25$$

Solution Steps

Since \frac{9}{4} and \frac{15}{4} have the same denominator, add them by adding their numerators.

$$\frac{9+15}{4}+\frac{33}{4}+\frac{63}{4}+\frac{129}{4}$$

Add 9 and 15 to get 24.

$$\frac{24}{4}+\frac{33}{4}+\frac{63}{4}+\frac{129}{4}$$

Since \frac{24}{4} and \frac{33}{4} have the same denominator, add them by adding their numerators.

$$\frac{24+33}{4}+\frac{63}{4}+\frac{129}{4}$$

Add 24 and 33 to get 57.

$$\frac{57}{4}+\frac{63}{4}+\frac{129}{4}$$

Since \frac{57}{4} and \frac{63}{4} have the same denominator, add them by adding their numerators.

$$\frac{57+63}{4}+\frac{129}{4}$$

Add 57 and 63 to get 120.

$$\frac{120}{4}+\frac{129}{4}$$

Since \frac{120}{4} and \frac{129}{4} have the same denominator, add them by adding their numerators.

$$\frac{120+129}{4}$$

Add 120 and 129 to get 249.

$$\frac{249}{4}$$

Factor

$$\frac{3 \cdot 83}{2 ^ {2}} = 62\frac{1}{4} = 62.25$$