Solve 9*3*3-(27)/(3^3)^5*2^3=1/27

$$\frac { 9 \times 3 \times 3 - ( 27 ) } { ( 3 ^ { 3 } ) ^ { 5 } \times 2 ^ { 3 } } = \frac { 1 } { 27 }$$

Verify

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 5 to get 15.

$$\frac{9\times 3\times 3-27}{3^{15}\times 2^{3}}=\frac{1}{27}$$

Multiply 9 and 3 to get 27.

$$\frac{27\times 3-27}{3^{15}\times 2^{3}}=\frac{1}{27}$$

Multiply 27 and 3 to get 81.

$$\frac{81-27}{3^{15}\times 2^{3}}=\frac{1}{27}$$

Subtract 27 from 81 to get 54.

$$\frac{54}{3^{15}\times 2^{3}}=\frac{1}{27}$$

Calculate 3 to the power of 15 and get 14348907.

$$\frac{54}{14348907\times 2^{3}}=\frac{1}{27}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{54}{14348907\times 8}=\frac{1}{27}$$

Multiply 14348907 and 8 to get 114791256.

$$\frac{54}{114791256}=\frac{1}{27}$$

Reduce the fraction \frac{54}{114791256} to lowest terms by extracting and canceling out 54.

$$\frac{1}{2125764}=\frac{1}{27}$$

Least common multiple of 2125764 and 27 is 2125764. Convert \frac{1}{2125764} and \frac{1}{27} to fractions with denominator 2125764.

$$\frac{1}{2125764}=\frac{78732}{2125764}$$

Compare \frac{1}{2125764} and \frac{78732}{2125764}.

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