Solve 82,6^3+31,6^3/114,2-82,6*31,6

$$\frac { 82,6 ^ { 3 } + 31,6 ^ { 3 } } { 114,2 } - 82,6 \cdot 31,6$$

Evaluate

$$-\frac{34209034}{14275}\approx -2396,429702277$$

Solution Steps

Calculate 6 to the power of 3 and get 216.

$$\frac{82\times 216+31\times 6^{3}}{114,2}-82,6\times 31,6$$

Multiply 82 and 216 to get 17712.

$$\frac{17712+31\times 6^{3}}{114,2}-82,6\times 31,6$$

Calculate 6 to the power of 3 and get 216.

$$\frac{17712+31\times 216}{114,2}-82,6\times 31,6$$

Multiply 31 and 216 to get 6696.

$$\frac{17712+6696}{114,2}-82,6\times 31,6$$

Add 17712 and 6696 to get 24408.

$$\frac{24408}{114,2}-82,6\times 31,6$$

Expand \frac{24408}{114,2} by multiplying both numerator and the denominator by 10.

$$\frac{244080}{1142}-82,6\times 31,6$$

Reduce the fraction \frac{244080}{1142} to lowest terms by extracting and canceling out 2.

$$\frac{122040}{571}-82,6\times 31,6$$

Multiply 82,6 and 31,6 to get 2610,16.

$$\frac{122040}{571}-2610,16$$

Convert decimal number 2610,16 to fraction \frac{261016}{100}. Reduce the fraction \frac{261016}{100} to lowest terms by extracting and canceling out 4.

$$\frac{122040}{571}-\frac{65254}{25}$$

Least common multiple of 571 and 25 is 14275. Convert \frac{122040}{571} and \frac{65254}{25} to fractions with denominator 14275.

$$\frac{3051000}{14275}-\frac{37260034}{14275}$$

Since \frac{3051000}{14275} and \frac{37260034}{14275} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3051000-37260034}{14275}$$

Subtract 37260034 from 3051000 to get -34209034.

$$-\frac{34209034}{14275}$$

Factor

$$-\frac{34209034}{14275} = -2396\frac{6134}{14275} = -2396.4297022767078$$