Solve 8s^-3/7s^-3

$$\frac { 8 s ^ { - 3 } } { 7 s ^ { - 3 } }$$

Evaluate

$$\frac{8}{7}\approx 1.142857143$$

Steps for the Product of Two Exponentials

Use the rules of exponents to simplify the expression.

$$\left(8s^{-3}\right)^{1}\times \frac{1}{7s^{-3}}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$8^{1}\left(s^{-3}\right)^{1}\times \frac{1}{7}\times \frac{1}{s^{-3}}$$

Use the Commutative Property of Multiplication.

$$8^{1}\times \frac{1}{7}\left(s^{-3}\right)^{1}\times \frac{1}{s^{-3}}$$

To raise a power to another power, multiply the exponents.

$$8^{1}\times \frac{1}{7}s^{-3}s^{-3\left(-1\right)}$$

Multiply -3 times -1.

$$8^{1}\times \frac{1}{7}s^{-3}s^{3}$$

To multiply powers of the same base, add their exponents.

$$8^{1}\times \frac{1}{7}s^{-3+3}$$

Add the exponents -3 and 3.

$$8^{1}\times \frac{1}{7}s^{0}$$

Raise 8 to the power 1.

$$8\times \frac{1}{7}s^{0}$$

Multiply 8 times \frac{1}{7}.

$$\frac{8}{7}s^{0}$$

For any term t except 0, t^{0}=1.

$$\frac{8}{7}\times 1$$

For any term t, t\times 1=t and 1t=t.

$$\frac{8}{7}$$

Factor

$$\frac{2 ^ {3}}{7} = 1\frac{1}{7} = 1.1428571428571428$$