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Solve for h
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8-h=2h\left(-k+4\right)
Multiply both sides of the equation by -k+4.
8-h=-2hk+8h
Use the distributive property to multiply 2h by -k+4.
8-h+2hk=8h
Add 2hk to both sides.
8-h+2hk-8h=0
Subtract 8h from both sides.
8-9h+2hk=0
Combine -h and -8h to get -9h.
-9h+2hk=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
\left(-9+2k\right)h=-8
Combine all terms containing h.
\left(2k-9\right)h=-8
The equation is in standard form.
\frac{\left(2k-9\right)h}{2k-9}=-\frac{8}{2k-9}
Divide both sides by 2k-9.
h=-\frac{8}{2k-9}
Dividing by 2k-9 undoes the multiplication by 2k-9.
8-h=2h\left(-k+4\right)
Variable k cannot be equal to 4 since division by zero is not defined. Multiply both sides of the equation by -k+4.
8-h=-2hk+8h
Use the distributive property to multiply 2h by -k+4.
-2hk+8h=8-h
Swap sides so that all variable terms are on the left hand side.
-2hk=8-h-8h
Subtract 8h from both sides.
-2hk=8-9h
Combine -h and -8h to get -9h.
\left(-2h\right)k=8-9h
The equation is in standard form.
\frac{\left(-2h\right)k}{-2h}=\frac{8-9h}{-2h}
Divide both sides by -2h.
k=\frac{8-9h}{-2h}
Dividing by -2h undoes the multiplication by -2h.
k=\frac{9}{2}-\frac{4}{h}
Divide 8-9h by -2h.
k=\frac{9}{2}-\frac{4}{h}\text{, }k\neq 4
Variable k cannot be equal to 4.