Solve for x
x=0
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8+\left(x-2\right)\times 3=x+2
Variable x cannot be equal to any of the values -2,2 since division by zero is not defined. Multiply both sides of the equation by \left(x-2\right)\left(x+2\right), the least common multiple of x^{2}-4,x+2,x-2.
8+3x-6=x+2
Use the distributive property to multiply x-2 by 3.
2+3x=x+2
Subtract 6 from 8 to get 2.
2+3x-x=2
Subtract x from both sides.
2+2x=2
Combine 3x and -x to get 2x.
2x=2-2
Subtract 2 from both sides.
2x=0
Subtract 2 from 2 to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since 2 is not equal to 0, x must be equal to 0.
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Limits
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