Factor
\frac{\left(2b-1\right)\left(4b^{2}+2b+1\right)}{3}
Evaluate
\frac{8b^{3}-1}{3}
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\frac{8b^{3}-1}{3}
Factor out \frac{1}{3}.
\left(2b-1\right)\left(4b^{2}+2b+1\right)
Consider 8b^{3}-1. Rewrite 8b^{3}-1 as \left(2b\right)^{3}-1^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
\frac{\left(2b-1\right)\left(4b^{2}+2b+1\right)}{3}
Rewrite the complete factored expression. Polynomial 4b^{2}+2b+1 is not factored since it does not have any rational roots.
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