Solve 8/243*5+4/243*5

$$\frac { 8 } { 243 } \times 5 + \frac { 4 } { 243 } \times 5$$

Evaluate

$$\frac{20}{81}\approx 0.24691358$$

Solution Steps

Express \frac{8}{243}\times 5 as a single fraction.

$$\frac{8\times 5}{243}+\frac{4}{243}\times 5$$

Multiply 8 and 5 to get 40.

$$\frac{40}{243}+\frac{4}{243}\times 5$$

Express \frac{4}{243}\times 5 as a single fraction.

$$\frac{40}{243}+\frac{4\times 5}{243}$$

Multiply 4 and 5 to get 20.

$$\frac{40}{243}+\frac{20}{243}$$

Since \frac{40}{243} and \frac{20}{243} have the same denominator, add them by adding their numerators.

$$\frac{40+20}{243}$$

Add 40 and 20 to get 60.

$$\frac{60}{243}$$

Reduce the fraction \frac{60}{243} to lowest terms by extracting and canceling out 3.

$$\frac{20}{81}$$

Factor

$$\frac{2 ^ {2} \cdot 5}{3 ^ {4}} = 0.24691358024691357$$