Solve 8*18/81*16^-2

$$\frac { 8 \times 18 } { 81 \times 16 ^ { - 2 } }$$

Evaluate

$$\frac{4096}{9}\approx 455.111111111$$

Solution Steps

Cancel out 9 in both numerator and denominator.

$$\frac{2\times 8}{9\times 16^{-2}}$$

Multiply 2 and 8 to get 16.

$$\frac{16}{9\times 16^{-2}}$$

Calculate 16 to the power of -2 and get \frac{1}{256}.

$$\frac{16}{9\times \frac{1}{256}}$$

Multiply 9 and \frac{1}{256} to get \frac{9}{256}.

$$\frac{16}{\frac{9}{256}}$$

Divide 16 by \frac{9}{256} by multiplying 16 by the reciprocal of \frac{9}{256}.

$$16\times \frac{256}{9}$$

Multiply 16 and \frac{256}{9} to get \frac{4096}{9}.

$$\frac{4096}{9}$$

Factor

$$\frac{2 ^ {12}}{3 ^ {2}} = 455\frac{1}{9} = 455.1111111111111$$