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\frac{8\sqrt{3}\sqrt{6}}{\left(\sqrt{6}\right)^{2}}
Rationalize the denominator of \frac{8\sqrt{3}}{\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
\frac{8\sqrt{3}\sqrt{6}}{6}
The square of \sqrt{6} is 6.
\frac{8\sqrt{3}\sqrt{3}\sqrt{2}}{6}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{8\times 3\sqrt{2}}{6}
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{24\sqrt{2}}{6}
Multiply 8 and 3 to get 24.
4\sqrt{2}
Divide 24\sqrt{2} by 6 to get 4\sqrt{2}.