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\frac{\left(8+4\sqrt{3}\right)\times 3}{6\times 2}
Divide \frac{8+4\sqrt{3}}{6} by \frac{2}{3} by multiplying \frac{8+4\sqrt{3}}{6} by the reciprocal of \frac{2}{3}.
\frac{4\sqrt{3}+8}{2\times 2}
Cancel out 3 in both numerator and denominator.
\frac{4\sqrt{3}+8}{4}
Multiply 2 and 2 to get 4.
\sqrt{3}+2
Divide each term of 4\sqrt{3}+8 by 4 to get \sqrt{3}+2.