Solve 7x/6xy-9x3/8x^3

$$\frac { 7 x } { 6 x y } - \frac { 9 x 3 } { 8 x ^ { 3 } }$$

Evaluate

$$\frac{7}{6y}-\frac{9x_{3}}{8x^{3}}$$

Short Solution Steps

Cancel out x in both numerator and denominator.

$$\frac{7}{6y}-\frac{9x_{3}}{8x^{3}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 6y and 8x^{3} is 24yx^{3}. Multiply \frac{7}{6y} times \frac{4x^{3}}{4x^{3}}. Multiply \frac{9x_{3}}{8x^{3}} times \frac{3y}{3y}.

$$\frac{7\times 4x^{3}}{24yx^{3}}-\frac{9x_{3}\times 3y}{24yx^{3}}$$

Since \frac{7\times 4x^{3}}{24yx^{3}} and \frac{9x_{3}\times 3y}{24yx^{3}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7\times 4x^{3}-9x_{3}\times 3y}{24yx^{3}}$$

Do the multiplications in 7\times 4x^{3}-9x_{3}\times 3y.

$$\frac{28x^{3}-27x_{3}y}{24yx^{3}}$$

Factor

$$\frac{28-\frac{27x_{3}y}{x^{3}}}{24y}$$