Solve 7w^2+49w+42/21w+21*w-6/w^2-36

$$\frac { 7 w ^ { 2 } + 49 w + 42 } { 21 w + 21 } \cdot \frac { w - 6 } { w ^ { 2 } - 36 }$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{7w^{2}+49w+42}{21w+21}.

$$\frac{7\left(w+1\right)\left(w+6\right)}{21\left(w+1\right)}\times \frac{w-6}{w^{2}-36}$$

Cancel out 7\left(w+1\right) in both numerator and denominator.

$$\frac{w+6}{3}\times \frac{w-6}{w^{2}-36}$$

Factor the expressions that are not already factored in \frac{w-6}{w^{2}-36}.

$$\frac{w+6}{3}\times \frac{w-6}{\left(w-6\right)\left(w+6\right)}$$

Cancel out w-6 in both numerator and denominator.

$$\frac{w+6}{3}\times \frac{1}{w+6}$$

Multiply \frac{w+6}{3} times \frac{1}{w+6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{w+6}{3\left(w+6\right)}$$

Cancel out w+6 in both numerator and denominator.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$