Solve 7/9-2.25*4/3div(-27/2)

$$\frac { 7 } { 9 } - 2.25 \times \frac { 4 } { 3 } \div ( - \frac { 27 } { 2 } )$$

Evaluate

$$1$$

Solution Steps

Convert decimal number 2.25 to fraction \frac{225}{100}. Reduce the fraction \frac{225}{100} to lowest terms by extracting and canceling out 25.

$$\frac{7}{9}-\frac{\frac{9}{4}\times \frac{4}{3}}{-\frac{27}{2}}$$

Multiply \frac{9}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{9}-\frac{\frac{9\times 4}{4\times 3}}{-\frac{27}{2}}$$

Cancel out 4 in both numerator and denominator.

$$\frac{7}{9}-\frac{\frac{9}{3}}{-\frac{27}{2}}$$

Divide 9 by 3 to get 3.

$$\frac{7}{9}-\frac{3}{-\frac{27}{2}}$$

Divide 3 by -\frac{27}{2} by multiplying 3 by the reciprocal of -\frac{27}{2}.

$$\frac{7}{9}-3\left(-\frac{2}{27}\right)$$

Express 3\left(-\frac{2}{27}\right) as a single fraction.

$$\frac{7}{9}-\frac{3\left(-2\right)}{27}$$

Multiply 3 and -2 to get -6.

$$\frac{7}{9}-\frac{-6}{27}$$

Reduce the fraction \frac{-6}{27} to lowest terms by extracting and canceling out 3.

$$\frac{7}{9}-\left(-\frac{2}{9}\right)$$

The opposite of -\frac{2}{9} is \frac{2}{9}.

$$\frac{7}{9}+\frac{2}{9}$$

Since \frac{7}{9} and \frac{2}{9} have the same denominator, add them by adding their numerators.

$$\frac{7+2}{9}$$

Add 7 and 2 to get 9.

$$\frac{9}{9}$$

Divide 9 by 9 to get 1.

$$1$$

Factor

$$1$$