Solve 7/8+12/3-5/4+1=

$$\frac { 7 } { 8 } + 1 \frac { 2 } { 3 } - \frac { 5 } { 4 } + 1 =$$

Evaluate

$$\frac{55}{24}\approx 2.291666667$$

Solution Steps

Multiply 1 and 3 to get 3.

$$\frac{7}{8}+\frac{3+2}{3}-\frac{5}{4}+1$$

Add 3 and 2 to get 5.

$$\frac{7}{8}+\frac{5}{3}-\frac{5}{4}+1$$

Least common multiple of 8 and 3 is 24. Convert \frac{7}{8} and \frac{5}{3} to fractions with denominator 24.

$$\frac{21}{24}+\frac{40}{24}-\frac{5}{4}+1$$

Since \frac{21}{24} and \frac{40}{24} have the same denominator, add them by adding their numerators.

$$\frac{21+40}{24}-\frac{5}{4}+1$$

Add 21 and 40 to get 61.

$$\frac{61}{24}-\frac{5}{4}+1$$

Least common multiple of 24 and 4 is 24. Convert \frac{61}{24} and \frac{5}{4} to fractions with denominator 24.

$$\frac{61}{24}-\frac{30}{24}+1$$

Since \frac{61}{24} and \frac{30}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{61-30}{24}+1$$

Subtract 30 from 61 to get 31.

$$\frac{31}{24}+1$$

Convert 1 to fraction \frac{24}{24}.

$$\frac{31}{24}+\frac{24}{24}$$

Since \frac{31}{24} and \frac{24}{24} have the same denominator, add them by adding their numerators.

$$\frac{31+24}{24}$$

Add 31 and 24 to get 55.

$$\frac{55}{24}$$

Factor

$$\frac{5 \cdot 11}{2 ^ {3} \cdot 3} = 2\frac{7}{24} = 2.2916666666666665$$