Solve 7/3+5-7/3+1<c

$$\frac { 7 } { 3 + 5 } - \frac { 7 } { 3 + 1 } < c$$

Solve for c

$$c>-\frac{7}{8}$$

Solution Steps

Add 3 and 5 to get 8.

$$\frac{7}{8}-\frac{7}{3+1}<c$$

Add 3 and 1 to get 4.

$$\frac{7}{8}-\frac{7}{4}<c$$

Least common multiple of 8 and 4 is 8. Convert \frac{7}{8} and \frac{7}{4} to fractions with denominator 8.

$$\frac{7}{8}-\frac{14}{8}<c$$

Since \frac{7}{8} and \frac{14}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-14}{8}<c$$

Subtract 14 from 7 to get -7.

$$-\frac{7}{8}<c$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$c>-\frac{7}{8}$$