Solve 7/0+4+3/0-4=3(0)+8/(0)^2-76

$$\frac { 7 } { 0 + 4 } + \frac { 3 } { 0 - 4 } = \frac { 3 ( 0 ) + 8 } { ( 0 ) ^ { 2 } - 76 }$$

Verify

Solution Steps

Add 0 and 4 to get 4.

$$\frac{7}{4}+\frac{3}{0-4}=\frac{3\times 0+8}{0^{2}-76}$$

Subtract 4 from 0 to get -4.

$$\frac{7}{4}+\frac{3}{-4}=\frac{3\times 0+8}{0^{2}-76}$$

Fraction \frac{3}{-4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$\frac{7}{4}-\frac{3}{4}=\frac{3\times 0+8}{0^{2}-76}$$

Since \frac{7}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-3}{4}=\frac{3\times 0+8}{0^{2}-76}$$

Subtract 3 from 7 to get 4.

$$\frac{4}{4}=\frac{3\times 0+8}{0^{2}-76}$$

Divide 4 by 4 to get 1.

$$1=\frac{3\times 0+8}{0^{2}-76}$$

Multiply 3 and 0 to get 0.

$$1=\frac{0+8}{0^{2}-76}$$

Add 0 and 8 to get 8.

$$1=\frac{8}{0^{2}-76}$$

Calculate 0 to the power of 2 and get 0.

$$1=\frac{8}{0-76}$$

Subtract 76 from 0 to get -76.

$$1=\frac{8}{-76}$$

Reduce the fraction \frac{8}{-76} to lowest terms by extracting and canceling out 4.

$$1=-\frac{2}{19}$$

Convert 1 to fraction \frac{19}{19}.

$$\frac{19}{19}=-\frac{2}{19}$$

Compare \frac{19}{19} and -\frac{2}{19}.

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