Solve 64/3+64-120-(8/3+4-60)

$$\frac { 64 } { 3 } + 64 - 120 - ( \frac { 8 } { 3 } + 4 - 60 )$$

Evaluate

$$\frac{56}{3}\approx 18.666666667$$

Solution Steps

Convert 64 to fraction \frac{192}{3}.

$$\frac{64}{3}+\frac{192}{3}-120-\left(\frac{8}{3}+4-60\right)$$

Since \frac{64}{3} and \frac{192}{3} have the same denominator, add them by adding their numerators.

$$\frac{64+192}{3}-120-\left(\frac{8}{3}+4-60\right)$$

Add 64 and 192 to get 256.

$$\frac{256}{3}-120-\left(\frac{8}{3}+4-60\right)$$

Convert 120 to fraction \frac{360}{3}.

$$\frac{256}{3}-\frac{360}{3}-\left(\frac{8}{3}+4-60\right)$$

Since \frac{256}{3} and \frac{360}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{256-360}{3}-\left(\frac{8}{3}+4-60\right)$$

Subtract 360 from 256 to get -104.

$$-\frac{104}{3}-\left(\frac{8}{3}+4-60\right)$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{104}{3}-\left(\frac{8}{3}+\frac{12}{3}-60\right)$$

Since \frac{8}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$-\frac{104}{3}-\left(\frac{8+12}{3}-60\right)$$

Add 8 and 12 to get 20.

$$-\frac{104}{3}-\left(\frac{20}{3}-60\right)$$

Convert 60 to fraction \frac{180}{3}.

$$-\frac{104}{3}-\left(\frac{20}{3}-\frac{180}{3}\right)$$

Since \frac{20}{3} and \frac{180}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{104}{3}-\frac{20-180}{3}$$

Subtract 180 from 20 to get -160.

$$-\frac{104}{3}-\left(-\frac{160}{3}\right)$$

The opposite of -\frac{160}{3} is \frac{160}{3}.

$$-\frac{104}{3}+\frac{160}{3}$$

Since -\frac{104}{3} and \frac{160}{3} have the same denominator, add them by adding their numerators.

$$\frac{-104+160}{3}$$

Add -104 and 160 to get 56.

$$\frac{56}{3}$$

Factor

$$\frac{2 ^ {3} \cdot 7}{3} = 18\frac{2}{3} = 18.666666666666668$$