Solve 6x^2-12xy+6y^2/3x^2-3y^2=?

$$\frac { 6 x ^ { 2 } - 12 x y + 6 y ^ { 2 } } { 3 x ^ { 2 } - 3 y ^ { 2 } } = ?$$

Evaluate

$$\frac{2\left(x-y\right)}{x+y}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{6\left(x-y\right)^{2}}{3\left(x+y\right)\left(x-y\right)}$$

Cancel out 3\left(x-y\right) in both numerator and denominator.

$$\frac{2\left(x-y\right)}{x+y}$$

Expand the expression.

$$\frac{2x-2y}{x+y}$$

Expand

$$-\frac{2\left(y-x\right)}{x+y}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{6\left(x-y\right)^{2}}{3\left(x+y\right)\left(x-y\right)}$$

Cancel out 3\left(x-y\right) in both numerator and denominator.

$$\frac{2\left(x-y\right)}{x+y}$$

Expand the expression.

$$\frac{2x-2y}{x+y}$$