Solve for x
x\leq \frac{73}{6}
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6x+7\leq 10\times 8
Multiply both sides by 8. Since 8 is positive, the inequality direction remains the same.
6x+7\leq 80
Multiply 10 and 8 to get 80.
6x\leq 80-7
Subtract 7 from both sides.
6x\leq 73
Subtract 7 from 80 to get 73.
x\leq \frac{73}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
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Limits
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