Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

\left(x+3\right)\left(6x+1\right)=\left(3x-2\right)\left(2x+5\right)
Variable x cannot be equal to any of the values -3,\frac{2}{3} since division by zero is not defined. Multiply both sides of the equation by \left(3x-2\right)\left(x+3\right), the least common multiple of 3x-2,x+3.
6x^{2}+19x+3=\left(3x-2\right)\left(2x+5\right)
Use the distributive property to multiply x+3 by 6x+1 and combine like terms.
6x^{2}+19x+3=6x^{2}+11x-10
Use the distributive property to multiply 3x-2 by 2x+5 and combine like terms.
6x^{2}+19x+3-6x^{2}=11x-10
Subtract 6x^{2} from both sides.
19x+3=11x-10
Combine 6x^{2} and -6x^{2} to get 0.
19x+3-11x=-10
Subtract 11x from both sides.
8x+3=-10
Combine 19x and -11x to get 8x.
8x=-10-3
Subtract 3 from both sides.
8x=-13
Subtract 3 from -10 to get -13.
x=\frac{-13}{8}
Divide both sides by 8.
x=-\frac{13}{8}
Fraction \frac{-13}{8} can be rewritten as -\frac{13}{8} by extracting the negative sign.