Solve 6n^2+11n-10/3n^2+19n-14*2n^2+6n-56/2n^2-3n-20

$$\frac { 6 n ^ { 2 } + 11 n - 10 } { 3 n ^ { 2 } + 19 n - 14 } \times \frac { 2 n ^ { 2 } + 6 n - 56 } { 2 n ^ { 2 } - 3 n - 20 }$$

Evaluate

$$2$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{6n^{2}+11n-10}{3n^{2}+19n-14}.

$$\frac{\left(3n-2\right)\left(2n+5\right)}{\left(3n-2\right)\left(n+7\right)}\times \frac{2n^{2}+6n-56}{2n^{2}-3n-20}$$

Cancel out 3n-2 in both numerator and denominator.

$$\frac{2n+5}{n+7}\times \frac{2n^{2}+6n-56}{2n^{2}-3n-20}$$

Factor the expressions that are not already factored in \frac{2n^{2}+6n-56}{2n^{2}-3n-20}.

$$\frac{2n+5}{n+7}\times \frac{2\left(n-4\right)\left(n+7\right)}{\left(n-4\right)\left(2n+5\right)}$$

Cancel out n-4 in both numerator and denominator.

$$\frac{2n+5}{n+7}\times \frac{2\left(n+7\right)}{2n+5}$$

Multiply \frac{2n+5}{n+7} times \frac{2\left(n+7\right)}{2n+5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(2n+5\right)\times 2\left(n+7\right)}{\left(n+7\right)\left(2n+5\right)}$$

Cancel out \left(n+7\right)\left(2n+5\right) in both numerator and denominator.

$$2$$

Factor

$$2$$