Solve 6k^2-3k/3k^2+1=2

$$\frac { 6 k ^ { 2 } - 3 k } { 3 k ^ { 2 } + 1 } = 2$$

Solve for k

$$k=-\frac{2}{3}\approx -0.666666667$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3k^{2}+1.

$$6k^{2}-3k=2\left(3k^{2}+1\right)$$

Use the distributive property to multiply 2 by 3k^{2}+1.

$$6k^{2}-3k=6k^{2}+2$$

Subtract 6k^{2} from both sides.

$$6k^{2}-3k-6k^{2}=2$$

Combine 6k^{2} and -6k^{2} to get 0.

$$-3k=2$$

Divide both sides by -3.

$$k=\frac{2}{-3}$$

Fraction \frac{2}{-3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$k=-\frac{2}{3}$$