Solve 6/k+2+3=8/k+2

$$\frac { 6 } { k + 2 } + 3 = \frac { 8 } { k + 2 }$$

Solve for k

$$k = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Steps for Solving Linear Equation

Variable k cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by k+2.

$$6+\left(k+2\right)\times 3=8$$

Use the distributive property to multiply k+2 by 3.

$$6+3k+6=8$$

Add 6 and 6 to get 12.

$$12+3k=8$$

Subtract 12 from both sides.

$$3k=8-12$$

Subtract 12 from 8 to get -4.

$$3k=-4$$

Divide both sides by 3.

$$k=\frac{-4}{3}$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$k=-\frac{4}{3}$$