Solve 6/17+2/102+1/34+8/6

$$\frac { 6 } { 17 } + \frac { 2 } { 102 } + \frac { 1 } { 34 } + \frac { 8 } { 6 }$$

Evaluate

$$\frac{59}{34}\approx 1.735294118$$

Solution Steps

Reduce the fraction \frac{2}{102} to lowest terms by extracting and canceling out 2.

$$\frac{6}{17}+\frac{1}{51}+\frac{1}{34}+\frac{8}{6}$$

Least common multiple of 17 and 51 is 51. Convert \frac{6}{17} and \frac{1}{51} to fractions with denominator 51.

$$\frac{18}{51}+\frac{1}{51}+\frac{1}{34}+\frac{8}{6}$$

Since \frac{18}{51} and \frac{1}{51} have the same denominator, add them by adding their numerators.

$$\frac{18+1}{51}+\frac{1}{34}+\frac{8}{6}$$

Add 18 and 1 to get 19.

$$\frac{19}{51}+\frac{1}{34}+\frac{8}{6}$$

Least common multiple of 51 and 34 is 102. Convert \frac{19}{51} and \frac{1}{34} to fractions with denominator 102.

$$\frac{38}{102}+\frac{3}{102}+\frac{8}{6}$$

Since \frac{38}{102} and \frac{3}{102} have the same denominator, add them by adding their numerators.

$$\frac{38+3}{102}+\frac{8}{6}$$

Add 38 and 3 to get 41.

$$\frac{41}{102}+\frac{8}{6}$$

Reduce the fraction \frac{8}{6} to lowest terms by extracting and canceling out 2.

$$\frac{41}{102}+\frac{4}{3}$$

Least common multiple of 102 and 3 is 102. Convert \frac{41}{102} and \frac{4}{3} to fractions with denominator 102.

$$\frac{41}{102}+\frac{136}{102}$$

Since \frac{41}{102} and \frac{136}{102} have the same denominator, add them by adding their numerators.

$$\frac{41+136}{102}$$

Add 41 and 136 to get 177.

$$\frac{177}{102}$$

Reduce the fraction \frac{177}{102} to lowest terms by extracting and canceling out 3.

$$\frac{59}{34}$$

Factor

$$\frac{59}{2 \cdot 17} = 1\frac{25}{34} = 1.7352941176470589$$