Solve 6+2+2*8/(17-2*3)^2

$$\frac { 6 + 2 + 2 \cdot 8 } { ( 17 - 2 \cdot 3 ) ^ { 2 } }$$

Evaluate

$$\frac{24}{121}\approx 0.198347107$$

Solution Steps

Add 6 and 2 to get 8.

$$\frac{8+2\times 8}{\left(17-2\times 3\right)^{2}}$$

Multiply 2 and 8 to get 16.

$$\frac{8+16}{\left(17-2\times 3\right)^{2}}$$

Add 8 and 16 to get 24.

$$\frac{24}{\left(17-2\times 3\right)^{2}}$$

Multiply 2 and 3 to get 6.

$$\frac{24}{\left(17-6\right)^{2}}$$

Subtract 6 from 17 to get 11.

$$\frac{24}{11^{2}}$$

Calculate 11 to the power of 2 and get 121.

$$\frac{24}{121}$$

Factor

$$\frac{2 ^ {3} \cdot 3}{11 ^ {2}} = 0.19834710743801653$$