Skip to main content
Solve for P_2
Tick mark Image

Similar Problems from Web Search

Share

4\left(6+18P_{2}\right)+3\left(4+8P_{2}\right)=204P_{2}
Variable P_{2} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 12P_{2}, the least common multiple of 3P_{2},4P_{2}.
24+72P_{2}+3\left(4+8P_{2}\right)=204P_{2}
Use the distributive property to multiply 4 by 6+18P_{2}.
24+72P_{2}+12+24P_{2}=204P_{2}
Use the distributive property to multiply 3 by 4+8P_{2}.
36+72P_{2}+24P_{2}=204P_{2}
Add 24 and 12 to get 36.
36+96P_{2}=204P_{2}
Combine 72P_{2} and 24P_{2} to get 96P_{2}.
36+96P_{2}-204P_{2}=0
Subtract 204P_{2} from both sides.
36-108P_{2}=0
Combine 96P_{2} and -204P_{2} to get -108P_{2}.
-108P_{2}=-36
Subtract 36 from both sides. Anything subtracted from zero gives its negation.
P_{2}=\frac{-36}{-108}
Divide both sides by -108.
P_{2}=\frac{1}{3}
Reduce the fraction \frac{-36}{-108} to lowest terms by extracting and canceling out -36.