Solve 56/ax-ay-3a/6y-6x=5b/-a(x-y)-3a/6(y-x)=

$$\frac { 56 } { a x - a y } - \frac { 3 a } { 6 y - 6 x } = \frac { 5 b } { - a ( x - y ) } - \frac { 3 a } { 6 ( y - x ) } =$$

Solve for b

$$b = -\frac{56}{5} = -11\frac{1}{5} = -11.2$$

$$x\neq y\text{ and }a\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6a\left(-x+y\right), the least common multiple of ax-ay,6y-6x,6\left(y-x\right).

$$-6\times 56-a\times 3a=6\times 5b-a\times 3a$$

Multiply -6 and 56 to get -336.

$$-336-a\times 3a=6\times 5b-a\times 3a$$

Multiply a and a to get a^{2}.

$$-336-a^{2}\times 3=6\times 5b-a\times 3a$$

Multiply a and a to get a^{2}.

$$-336-a^{2}\times 3=6\times 5b-a^{2}\times 3$$

Multiply 6 and 5 to get 30.

$$-336-a^{2}\times 3=30b-a^{2}\times 3$$

Swap sides so that all variable terms are on the left hand side.

$$30b-a^{2}\times 3=-336-a^{2}\times 3$$

Add a^{2}\times 3 to both sides.

$$30b=-336-a^{2}\times 3+a^{2}\times 3$$

Multiply -1 and 3 to get -3.

$$30b=-336-3a^{2}+a^{2}\times 3$$

Combine -3a^{2} and a^{2}\times 3 to get 0.

$$30b=-336$$

Divide both sides by 30.

$$b=\frac{-336}{30}$$

Reduce the fraction \frac{-336}{30} to lowest terms by extracting and canceling out 6.

$$b=-\frac{56}{5}$$

Solve for a

$$a\neq 0$$

$$b=-\frac{56}{5}\text{ and }x\neq y$$