Solve 5x^7/3x^2-3(x

$$\frac { 5 x ^ { 7 } } { 3 x ^ { 2 } } - 3 ( x$$

Evaluate

$$\frac{5x^{5}}{3}-3x$$

Short Solution Steps

Cancel out x^{2} in both numerator and denominator.

$$\frac{5x^{5}}{3}-3x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -3x times \frac{3}{3}.

$$\frac{5x^{5}}{3}+\frac{3\left(-3\right)x}{3}$$

Since \frac{5x^{5}}{3} and \frac{3\left(-3\right)x}{3} have the same denominator, add them by adding their numerators.

$$\frac{5x^{5}+3\left(-3\right)x}{3}$$

Do the multiplications in 5x^{5}+3\left(-3\right)x.

$$\frac{5x^{5}-9x}{3}$$

Factor

$$\frac{x\left(5x^{4}-9\right)}{3}$$

Solution Steps

Cancel out x^{2} in both numerator and denominator.

$$factor(\frac{5x^{5}}{3}-3x)$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -3x times \frac{3}{3}.

$$factor(\frac{5x^{5}}{3}+\frac{3\left(-3\right)x}{3})$$

Since \frac{5x^{5}}{3} and \frac{3\left(-3\right)x}{3} have the same denominator, add them by adding their numerators.

$$factor(\frac{5x^{5}+3\left(-3\right)x}{3})$$

Do the multiplications in 5x^{5}+3\left(-3\right)x.

$$factor(\frac{5x^{5}-9x}{3})$$

Consider 5x^{5}-9x. Factor out x.

$$x\left(5x^{4}-9\right)$$

Rewrite the complete factored expression. Polynomial 5x^{4}-9 is not factored since it does not have any rational roots.

$$\frac{x\left(5x^{4}-9\right)}{3}$$