Solve 5s-6/8s^4-2-3s/8s^4-2

$$\frac { 5 s - 6 } { 8 s ^ { 4 } - 2 } - \frac { 3 s } { 8 s ^ { 4 } - 2 }$$

Evaluate

$$\frac{s-3}{4s^{4}-1}$$

Short Solution Steps

Since \frac{5s-6}{8s^{4}-2} and \frac{3s}{8s^{4}-2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5s-6-3s}{8s^{4}-2}$$

Combine like terms in 5s-6-3s.

$$\frac{2s-6}{8s^{4}-2}$$

Factor the expressions that are not already factored in \frac{2s-6}{8s^{4}-2}.

$$\frac{2\left(s-3\right)}{2\left(2s^{2}-1\right)\left(2s^{2}+1\right)}$$

Cancel out 2 in both numerator and denominator.

$$\frac{s-3}{\left(2s^{2}-1\right)\left(2s^{2}+1\right)}$$

Expand \left(2s^{2}-1\right)\left(2s^{2}+1\right).

$$\frac{s-3}{4s^{4}-1}$$

Expand

$$\frac{s-3}{4s^{4}-1}$$

Short Solution Steps

Since \frac{5s-6}{8s^{4}-2} and \frac{3s}{8s^{4}-2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5s-6-3s}{8s^{4}-2}$$

Combine like terms in 5s-6-3s.

$$\frac{2s-6}{8s^{4}-2}$$

Factor the expressions that are not already factored in \frac{2s-6}{8s^{4}-2}.

$$\frac{2\left(s-3\right)}{2\left(2s^{2}-1\right)\left(2s^{2}+1\right)}$$

Cancel out 2 in both numerator and denominator.

$$\frac{s-3}{\left(2s^{2}-1\right)\left(2s^{2}+1\right)}$$

Expand \left(2s^{2}-1\right)\left(2s^{2}+1\right).

$$\frac{s-3}{4s^{4}-1}$$