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8\times 5=yy
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8y, the least common multiple of y,8.
8\times 5=y^{2}
Multiply y and y to get y^{2}.
40=y^{2}
Multiply 8 and 5 to get 40.
y^{2}=40
Swap sides so that all variable terms are on the left hand side.
y=2\sqrt{10} y=-2\sqrt{10}
Take the square root of both sides of the equation.
8\times 5=yy
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8y, the least common multiple of y,8.
8\times 5=y^{2}
Multiply y and y to get y^{2}.
40=y^{2}
Multiply 8 and 5 to get 40.
y^{2}=40
Swap sides so that all variable terms are on the left hand side.
y^{2}-40=0
Subtract 40 from both sides.
y=\frac{0±\sqrt{0^{2}-4\left(-40\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -40 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{0±\sqrt{-4\left(-40\right)}}{2}
Square 0.
y=\frac{0±\sqrt{160}}{2}
Multiply -4 times -40.
y=\frac{0±4\sqrt{10}}{2}
Take the square root of 160.
y=2\sqrt{10}
Now solve the equation y=\frac{0±4\sqrt{10}}{2} when ± is plus.
y=-2\sqrt{10}
Now solve the equation y=\frac{0±4\sqrt{10}}{2} when ± is minus.
y=2\sqrt{10} y=-2\sqrt{10}
The equation is now solved.