Solve 5/t+8-10t

$$\frac { 5 } { t + 8 } - 10 t$$

Evaluate

$$\frac{5\left(1-16t-2t^{2}\right)}{t+8}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -10t times \frac{t+8}{t+8}.

$$\frac{5}{t+8}+\frac{-10t\left(t+8\right)}{t+8}$$

Since \frac{5}{t+8} and \frac{-10t\left(t+8\right)}{t+8} have the same denominator, add them by adding their numerators.

$$\frac{5-10t\left(t+8\right)}{t+8}$$

Do the multiplications in 5-10t\left(t+8\right).

$$\frac{5-10t^{2}-80t}{t+8}$$

Factor

$$-\frac{10\left(t-\left(-\frac{\sqrt{66}}{2}-4\right)\right)\left(t-\left(\frac{\sqrt{66}}{2}-4\right)\right)}{t+8}$$