Solve 5/9*6/4-(4/9div10/3)=

$$\frac { 5 } { 9 } \times \frac { 6 } { 4 } - ( \frac { 4 } { 9 } \div \frac { 10 } { 3 } ) =$$

Evaluate

$$\frac{7}{10}=0.7$$

Solution Steps

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{5}{9}\times \frac{3}{2}-\frac{\frac{4}{9}}{\frac{10}{3}}$$

Multiply \frac{5}{9} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 3}{9\times 2}-\frac{\frac{4}{9}}{\frac{10}{3}}$$

Do the multiplications in the fraction \frac{5\times 3}{9\times 2}.

$$\frac{15}{18}-\frac{\frac{4}{9}}{\frac{10}{3}}$$

Reduce the fraction \frac{15}{18} to lowest terms by extracting and canceling out 3.

$$\frac{5}{6}-\frac{\frac{4}{9}}{\frac{10}{3}}$$

Divide \frac{4}{9} by \frac{10}{3} by multiplying \frac{4}{9} by the reciprocal of \frac{10}{3}.

$$\frac{5}{6}-\frac{4}{9}\times \frac{3}{10}$$

Multiply \frac{4}{9} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{6}-\frac{4\times 3}{9\times 10}$$

Do the multiplications in the fraction \frac{4\times 3}{9\times 10}.

$$\frac{5}{6}-\frac{12}{90}$$

Reduce the fraction \frac{12}{90} to lowest terms by extracting and canceling out 6.

$$\frac{5}{6}-\frac{2}{15}$$

Least common multiple of 6 and 15 is 30. Convert \frac{5}{6} and \frac{2}{15} to fractions with denominator 30.

$$\frac{25}{30}-\frac{4}{30}$$

Since \frac{25}{30} and \frac{4}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-4}{30}$$

Subtract 4 from 25 to get 21.

$$\frac{21}{30}$$

Reduce the fraction \frac{21}{30} to lowest terms by extracting and canceling out 3.

$$\frac{7}{10}$$

Factor

$$\frac{7}{2 \cdot 5} = 0.7$$