Solve for x
x=-2
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Linear Equation
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\frac { 5 } { 8 } x + \frac { 3 } { 4 } = \frac { 1 } { 4 } x
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\frac{5}{8}x+\frac{3}{4}-\frac{1}{4}x=0
Subtract \frac{1}{4}x from both sides.
\frac{3}{8}x+\frac{3}{4}=0
Combine \frac{5}{8}x and -\frac{1}{4}x to get \frac{3}{8}x.
\frac{3}{8}x=-\frac{3}{4}
Subtract \frac{3}{4} from both sides. Anything subtracted from zero gives its negation.
x=-\frac{3}{4}\times \frac{8}{3}
Multiply both sides by \frac{8}{3}, the reciprocal of \frac{3}{8}.
x=\frac{-3\times 8}{4\times 3}
Multiply -\frac{3}{4} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-24}{12}
Do the multiplications in the fraction \frac{-3\times 8}{4\times 3}.
x=-2
Divide -24 by 12 to get -2.
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