Solve 5/8a^4b^8:(-5/8a^4b^8)

$$\frac { 5 } { 8 } a ^ { 4 } b ^ { 8 } : ( - \frac { 5 } { 8 } a ^ { 4 } b ^ { 8 } )$$

Evaluate

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Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{\left(\frac{5}{8}\right)^{1}a^{4}b^{8}}{\left(-\frac{5}{8}\right)^{1}a^{4}b^{8}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\left(\frac{5}{8}\right)^{1}}{\left(-\frac{5}{8}\right)^{1}}a^{4-4}b^{8-8}$$

Subtract 4 from 4.

$$\frac{\left(\frac{5}{8}\right)^{1}}{\left(-\frac{5}{8}\right)^{1}}a^{0}b^{8-8}$$

For any number a except 0, a^{0}=1.

$$\frac{\left(\frac{5}{8}\right)^{1}}{\left(-\frac{5}{8}\right)^{1}}b^{8-8}$$

Subtract 8 from 8.

$$\frac{\left(\frac{5}{8}\right)^{1}}{\left(-\frac{5}{8}\right)^{1}}b^{0}$$

For any number a except 0, a^{0}=1.

$$\frac{\left(\frac{5}{8}\right)^{1}}{\left(-\frac{5}{8}\right)^{1}}$$

Divide \frac{5}{8} by -\frac{5}{8} by multiplying \frac{5}{8} by the reciprocal of -\frac{5}{8}.

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Factor

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