Solve 5/4^4*6^2+4/4^3*6^3=

$$\frac { 5 } { 4 ^ { 4 } \times 6 ^ { 2 } } + \frac { 4 } { 4 ^ { 3 } \times 6 ^ { 3 } } =$$

Evaluate

$$\frac{23}{27648}\approx 0.000831887$$

Solution Steps

Calculate 4 to the power of 4 and get 256.

$$\frac{5}{256\times 6^{2}}+\frac{4}{4^{3}\times 6^{3}}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{5}{256\times 36}+\frac{4}{4^{3}\times 6^{3}}$$

Multiply 256 and 36 to get 9216.

$$\frac{5}{9216}+\frac{4}{4^{3}\times 6^{3}}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{5}{9216}+\frac{4}{64\times 6^{3}}$$

Calculate 6 to the power of 3 and get 216.

$$\frac{5}{9216}+\frac{4}{64\times 216}$$

Multiply 64 and 216 to get 13824.

$$\frac{5}{9216}+\frac{4}{13824}$$

Reduce the fraction \frac{4}{13824} to lowest terms by extracting and canceling out 4.

$$\frac{5}{9216}+\frac{1}{3456}$$

Least common multiple of 9216 and 3456 is 27648. Convert \frac{5}{9216} and \frac{1}{3456} to fractions with denominator 27648.

$$\frac{15}{27648}+\frac{8}{27648}$$

Since \frac{15}{27648} and \frac{8}{27648} have the same denominator, add them by adding their numerators.

$$\frac{15+8}{27648}$$

Add 15 and 8 to get 23.

$$\frac{23}{27648}$$

Factor

$$\frac{23}{2 ^ {10} \cdot 3 ^ {3}} = 0.0008318865740740741$$