Solve 48*6^4/9*(3*2)^8

$$\frac { 48 \times 6 ^ { 4 } } { 9 \times ( 3 \times 2 ) ^ { 8 } }$$

Evaluate

$$\frac{1}{243}\approx 0.004115226$$

Solution Steps

Cancel out 3 in both numerator and denominator.

$$\frac{16\times 6^{4}}{3\times \left(2\times 3\right)^{8}}$$

Calculate 6 to the power of 4 and get 1296.

$$\frac{16\times 1296}{3\times \left(2\times 3\right)^{8}}$$

Multiply 16 and 1296 to get 20736.

$$\frac{20736}{3\times \left(2\times 3\right)^{8}}$$

Multiply 2 and 3 to get 6.

$$\frac{20736}{3\times 6^{8}}$$

Calculate 6 to the power of 8 and get 1679616.

$$\frac{20736}{3\times 1679616}$$

Multiply 3 and 1679616 to get 5038848.

$$\frac{20736}{5038848}$$

Reduce the fraction \frac{20736}{5038848} to lowest terms by extracting and canceling out 20736.

$$\frac{1}{243}$$

Factor

$$\frac{1}{3 ^ {5}} = 0.00411522633744856$$