Solve 40*4+4^2*2/90+5*12=?

$$\frac { 40 \times 4 + 4 ^ { 2 } \times 2 } { 90 + 5 \times 12 } = ?$$

Evaluate

$$\frac{32}{25}=1.28$$

Solution Steps

Multiply 40 and 4 to get 160.

$$\frac{160+4^{2}\times 2}{90+5\times 12}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{160+16\times 2}{90+5\times 12}$$

Multiply 16 and 2 to get 32.

$$\frac{160+32}{90+5\times 12}$$

Add 160 and 32 to get 192.

$$\frac{192}{90+5\times 12}$$

Multiply 5 and 12 to get 60.

$$\frac{192}{90+60}$$

Add 90 and 60 to get 150.

$$\frac{192}{150}$$

Reduce the fraction \frac{192}{150} to lowest terms by extracting and canceling out 6.

$$\frac{32}{25}$$

Factor

$$\frac{2 ^ {5}}{5 ^ {2}} = 1\frac{7}{25} = 1.28$$