Solve 4y/y^2

$$\frac { 4 y } { y ^ { 2 } }$$

Evaluate

$$\frac{4}{y}$$

Steps for the Product of Two Exponentials

Use the rules of exponents to simplify the expression.

$$\left(4y^{1}\right)^{1}\times \frac{1}{y^{2}}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$4^{1}\left(y^{1}\right)^{1}\times \frac{1}{1}\times \frac{1}{y^{2}}$$

Use the Commutative Property of Multiplication.

$$4^{1}\times \frac{1}{1}\left(y^{1}\right)^{1}\times \frac{1}{y^{2}}$$

To raise a power to another power, multiply the exponents.

$$4^{1}\times \frac{1}{1}y^{1}y^{2\left(-1\right)}$$

Multiply 2 times -1.

$$4^{1}\times \frac{1}{1}y^{1}y^{-2}$$

To multiply powers of the same base, add their exponents.

$$4^{1}\times \frac{1}{1}y^{1-2}$$

Add the exponents 1 and -2.

$$4^{1}\times \frac{1}{1}\times \frac{1}{y}$$

Raise 4 to the power 1.

$$4\times \frac{1}{1}\times \frac{1}{y}$$

Differentiate w.r.t. y

$$-\frac{4}{y^{2}}$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{4}{1}y^{1-2})$$

Do the arithmetic.

$$\frac{\mathrm{d}}{\mathrm{d}y}(4\times \frac{1}{y})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-4y^{-1-1}$$

Do the arithmetic.

$$-4y^{-2}$$