Solve for x
x=1
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Quadratic Equation
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\frac { 4 x } { x ^ { 2 } - 9 } = \frac { 2 } { x + 3 } - 1
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4x=\left(x-3\right)\times 2+\left(x-3\right)\left(x+3\right)\left(-1\right)
Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of x^{2}-9,x+3.
4x=2x-6+\left(x-3\right)\left(x+3\right)\left(-1\right)
Use the distributive property to multiply x-3 by 2.
4x=2x-6+\left(x^{2}-9\right)\left(-1\right)
Use the distributive property to multiply x-3 by x+3 and combine like terms.
4x=2x-6-x^{2}+9
Use the distributive property to multiply x^{2}-9 by -1.
4x=2x+3-x^{2}
Add -6 and 9 to get 3.
4x-2x=3-x^{2}
Subtract 2x from both sides.
2x=3-x^{2}
Combine 4x and -2x to get 2x.
2x-3=-x^{2}
Subtract 3 from both sides.
2x-3+x^{2}=0
Add x^{2} to both sides.
x^{2}+2x-3=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=2 ab=-3
To solve the equation, factor x^{2}+2x-3 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
a=-1 b=3
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(x-1\right)\left(x+3\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=1 x=-3
To find equation solutions, solve x-1=0 and x+3=0.
x=1
Variable x cannot be equal to -3.
4x=\left(x-3\right)\times 2+\left(x-3\right)\left(x+3\right)\left(-1\right)
Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of x^{2}-9,x+3.
4x=2x-6+\left(x-3\right)\left(x+3\right)\left(-1\right)
Use the distributive property to multiply x-3 by 2.
4x=2x-6+\left(x^{2}-9\right)\left(-1\right)
Use the distributive property to multiply x-3 by x+3 and combine like terms.
4x=2x-6-x^{2}+9
Use the distributive property to multiply x^{2}-9 by -1.
4x=2x+3-x^{2}
Add -6 and 9 to get 3.
4x-2x=3-x^{2}
Subtract 2x from both sides.
2x=3-x^{2}
Combine 4x and -2x to get 2x.
2x-3=-x^{2}
Subtract 3 from both sides.
2x-3+x^{2}=0
Add x^{2} to both sides.
x^{2}+2x-3=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=2 ab=1\left(-3\right)=-3
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-3. To find a and b, set up a system to be solved.
a=-1 b=3
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(x^{2}-x\right)+\left(3x-3\right)
Rewrite x^{2}+2x-3 as \left(x^{2}-x\right)+\left(3x-3\right).
x\left(x-1\right)+3\left(x-1\right)
Factor out x in the first and 3 in the second group.
\left(x-1\right)\left(x+3\right)
Factor out common term x-1 by using distributive property.
x=1 x=-3
To find equation solutions, solve x-1=0 and x+3=0.
x=1
Variable x cannot be equal to -3.
4x=\left(x-3\right)\times 2+\left(x-3\right)\left(x+3\right)\left(-1\right)
Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of x^{2}-9,x+3.
4x=2x-6+\left(x-3\right)\left(x+3\right)\left(-1\right)
Use the distributive property to multiply x-3 by 2.
4x=2x-6+\left(x^{2}-9\right)\left(-1\right)
Use the distributive property to multiply x-3 by x+3 and combine like terms.
4x=2x-6-x^{2}+9
Use the distributive property to multiply x^{2}-9 by -1.
4x=2x+3-x^{2}
Add -6 and 9 to get 3.
4x-2x=3-x^{2}
Subtract 2x from both sides.
2x=3-x^{2}
Combine 4x and -2x to get 2x.
2x-3=-x^{2}
Subtract 3 from both sides.
2x-3+x^{2}=0
Add x^{2} to both sides.
x^{2}+2x-3=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-2±\sqrt{2^{2}-4\left(-3\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 2 for b, and -3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2±\sqrt{4-4\left(-3\right)}}{2}
Square 2.
x=\frac{-2±\sqrt{4+12}}{2}
Multiply -4 times -3.
x=\frac{-2±\sqrt{16}}{2}
Add 4 to 12.
x=\frac{-2±4}{2}
Take the square root of 16.
x=\frac{2}{2}
Now solve the equation x=\frac{-2±4}{2} when ± is plus. Add -2 to 4.
x=1
Divide 2 by 2.
x=-\frac{6}{2}
Now solve the equation x=\frac{-2±4}{2} when ± is minus. Subtract 4 from -2.
x=-3
Divide -6 by 2.
x=1 x=-3
The equation is now solved.
x=1
Variable x cannot be equal to -3.
4x=\left(x-3\right)\times 2+\left(x-3\right)\left(x+3\right)\left(-1\right)
Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of x^{2}-9,x+3.
4x=2x-6+\left(x-3\right)\left(x+3\right)\left(-1\right)
Use the distributive property to multiply x-3 by 2.
4x=2x-6+\left(x^{2}-9\right)\left(-1\right)
Use the distributive property to multiply x-3 by x+3 and combine like terms.
4x=2x-6-x^{2}+9
Use the distributive property to multiply x^{2}-9 by -1.
4x=2x+3-x^{2}
Add -6 and 9 to get 3.
4x-2x=3-x^{2}
Subtract 2x from both sides.
2x=3-x^{2}
Combine 4x and -2x to get 2x.
2x+x^{2}=3
Add x^{2} to both sides.
x^{2}+2x=3
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+2x+1^{2}=3+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=3+1
Square 1.
x^{2}+2x+1=4
Add 3 to 1.
\left(x+1\right)^{2}=4
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
x+1=2 x+1=-2
Simplify.
x=1 x=-3
Subtract 1 from both sides of the equation.
x=1
Variable x cannot be equal to -3.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}