Solve 4x^3y/5x^3y=

$$\frac { 4 x ^ { 3 } y } { 5 x ^ { 3 } y } =$$

Evaluate

$$\frac{4}{5}=0.8$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{4^{1}x^{3}y^{1}}{5^{1}x^{3}y^{1}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{4^{1}}{5^{1}}x^{3-3}y^{1-1}$$

Subtract 3 from 3.

$$\frac{4^{1}}{5^{1}}x^{0}y^{1-1}$$

For any number a except 0, a^{0}=1.

$$\frac{4^{1}}{5^{1}}y^{1-1}$$

Subtract 1 from 1.

$$\frac{4^{1}}{5^{1}}y^{0}$$

For any number a except 0, a^{0}=1.

$$\frac{4^{1}}{5^{1}}$$

Divide 4 by 5.

$$\frac{4}{5}$$

Factor

$$\frac{2 ^ {2}}{5} = 0.8$$