Solve 4v^3-3v^2-v/v+4*v+4/4v+1

$$\frac { 4 v ^ { 3 } - 3 v ^ { 2 } - v } { v + 4 } \cdot \frac { v + 4 } { 4 v + 1 }$$

Evaluate

$$v\left(v-1\right)$$

Short Solution Steps

Multiply \frac{4v^{3}-3v^{2}-v}{v+4} times \frac{v+4}{4v+1} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(4v^{3}-3v^{2}-v\right)\left(v+4\right)}{\left(v+4\right)\left(4v+1\right)}$$

Cancel out v+4 in both numerator and denominator.

$$\frac{4v^{3}-3v^{2}-v}{4v+1}$$

Factor the expressions that are not already factored.

$$\frac{v\left(v-1\right)\left(4v+1\right)}{4v+1}$$

Cancel out 4v+1 in both numerator and denominator.

$$v\left(v-1\right)$$

Expand the expression.

$$v^{2}-v$$

Expand

$$v^{2}-v$$

Short Solution Steps

Multiply \frac{4v^{3}-3v^{2}-v}{v+4} times \frac{v+4}{4v+1} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(4v^{3}-3v^{2}-v\right)\left(v+4\right)}{\left(v+4\right)\left(4v+1\right)}$$

Cancel out v+4 in both numerator and denominator.

$$\frac{4v^{3}-3v^{2}-v}{4v+1}$$

Factor the expressions that are not already factored.

$$\frac{v\left(v-1\right)\left(4v+1\right)}{4v+1}$$

Cancel out 4v+1 in both numerator and denominator.

$$v\left(v-1\right)$$

Expand the expression.

$$v^{2}-v$$