Solve 4m/4=m^2+4x/4

$$\frac { 4 m } { 4 } = \frac { m ^ { 2 } + 4 x } { 4 }$$

Solve for x

$$x=-\frac{m^{2}}{4}+m$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$4m=m^{2}+4x$$

Swap sides so that all variable terms are on the left hand side.

$$m^{2}+4x=4m$$

Subtract m^{2} from both sides.

$$4x=4m-m^{2}$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{m\left(4-m\right)}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{m\left(4-m\right)}{4}$$

Divide m\left(4-m\right) by 4.

$$x=-\frac{m^{2}}{4}+m$$

Solve for m (complex solution)

$$m=-2\sqrt{1-x}+2$$

$$m=2\sqrt{1-x}+2$$

Solve for m

$$m=-2\sqrt{1-x}+2$$

$$m=2\sqrt{1-x}+2\text{, }x\leq 1$$