Solve 4R*4R/4R+4R

$$\frac { 4 R \times 4 R } { 4 R + 4 R }$$

Evaluate

$$2R$$

Solution Steps

Multiply R and R to get R^{2}.

$$\frac{4R^{2}\times 4}{4R+4R}$$

Multiply 4 and 4 to get 16.

$$\frac{16R^{2}}{4R+4R}$$

Combine 4R and 4R to get 8R.

$$\frac{16R^{2}}{8R}$$

Cancel out 8R in both numerator and denominator.

$$2R$$

Differentiate w.r.t. R

$$2$$

Steps Using Definition of a Derivative

Multiply R and R to get R^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}R}(\frac{4R^{2}\times 4}{4R+4R})$$

Multiply 4 and 4 to get 16.

$$\frac{\mathrm{d}}{\mathrm{d}R}(\frac{16R^{2}}{4R+4R})$$

Combine 4R and 4R to get 8R.

$$\frac{\mathrm{d}}{\mathrm{d}R}(\frac{16R^{2}}{8R})$$

Cancel out 8R in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}R}(2R)$$

The derivative of ax^{n} is nax^{n-1}.

$$2R^{1-1}$$

Subtract 1 from 1.

$$2R^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$