Solve 4/x+2-6/4x+8

$$\frac { 4 } { x + 2 } - \frac { 6 } { 4 x + 8 }$$

Evaluate

$$\frac{5}{2\left(x+2\right)}$$

Short Solution Steps

Factor 4x+8.

$$\frac{4}{x+2}-\frac{6}{4\left(x+2\right)}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+2 and 4\left(x+2\right) is 4\left(x+2\right). Multiply \frac{4}{x+2} times \frac{4}{4}.

$$\frac{4\times 4}{4\left(x+2\right)}-\frac{6}{4\left(x+2\right)}$$

Since \frac{4\times 4}{4\left(x+2\right)} and \frac{6}{4\left(x+2\right)} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4\times 4-6}{4\left(x+2\right)}$$

Do the multiplications in 4\times 4-6.

$$\frac{16-6}{4\left(x+2\right)}$$

Do the calculations in 16-6.

$$\frac{10}{4\left(x+2\right)}$$

Expand 4\left(x+2\right).

$$\frac{10}{4x+8}$$

Factor

$$\frac{5}{2\left(x+2\right)}$$