Solve 4/9+7*4/9+3

$$\frac { 4 } { 9 + 7 } \cdot \frac { 4 } { 9 + 3 }$$

Evaluate

$$\frac{1}{12}\approx 0.083333333$$

Solution Steps

Add 9 and 7 to get 16.

$$\frac{4}{16}\times \frac{4}{9+3}$$

Reduce the fraction \frac{4}{16} to lowest terms by extracting and canceling out 4.

$$\frac{1}{4}\times \frac{4}{9+3}$$

Add 9 and 3 to get 12.

$$\frac{1}{4}\times \frac{4}{12}$$

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{4}\times \frac{1}{3}$$

Multiply \frac{1}{4} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{4\times 3}$$

Do the multiplications in the fraction \frac{1\times 1}{4\times 3}.

$$\frac{1}{12}$$

Factor

$$\frac{1}{2 ^ {2} \cdot 3} = 0.08333333333333333$$