Solve 4/5-(2,4-g)-(1-3g)=0

$$\frac { 4 } { 5 } - ( 2,4 - g ) - ( 1 - 3 g ) = 0$$

Solve for g

$$g=0,65$$

Steps for Solving Linear Equation

To find the opposite of 2,4-g, find the opposite of each term.

$$\frac{4}{5}-2,4-\left(-g\right)-\left(1-3g\right)=0$$

The opposite of -g is g.

$$\frac{4}{5}-2,4+g-\left(1-3g\right)=0$$

Convert decimal number 2,4 to fraction \frac{24}{10}. Reduce the fraction \frac{24}{10} to lowest terms by extracting and canceling out 2.

$$\frac{4}{5}-\frac{12}{5}+g-\left(1-3g\right)=0$$

Since \frac{4}{5} and \frac{12}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-12}{5}+g-\left(1-3g\right)=0$$

Subtract 12 from 4 to get -8.

$$-\frac{8}{5}+g-\left(1-3g\right)=0$$

To find the opposite of 1-3g, find the opposite of each term.

$$-\frac{8}{5}+g-1-\left(-3g\right)=0$$

The opposite of -3g is 3g.

$$-\frac{8}{5}+g-1+3g=0$$

Convert 1 to fraction \frac{5}{5}.

$$-\frac{8}{5}+g-\frac{5}{5}+3g=0$$

Since -\frac{8}{5} and \frac{5}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-8-5}{5}+g+3g=0$$

Subtract 5 from -8 to get -13.

$$-\frac{13}{5}+g+3g=0$$

Combine g and 3g to get 4g.

$$-\frac{13}{5}+4g=0$$

Add \frac{13}{5} to both sides. Anything plus zero gives itself.

$$4g=\frac{13}{5}$$

Divide both sides by 4.

$$g=\frac{\frac{13}{5}}{4}$$

Express \frac{\frac{13}{5}}{4} as a single fraction.

$$g=\frac{13}{5\times 4}$$

Multiply 5 and 4 to get 20.

$$g=\frac{13}{20}$$