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\frac{4\sqrt{2}}{4\left(\sqrt{2}\right)^{2}}\times \frac{\sqrt{3}}{\sqrt{2}}
Rationalize the denominator of \frac{4}{4\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{4\sqrt{2}}{4\times 2}\times \frac{\sqrt{3}}{\sqrt{2}}
The square of \sqrt{2} is 2.
\frac{\sqrt{2}}{2}\times \frac{\sqrt{3}}{\sqrt{2}}
Cancel out 4 in both numerator and denominator.
\frac{\sqrt{2}}{2}\times \frac{\sqrt{3}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{3}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\sqrt{2}}{2}\times \frac{\sqrt{3}\sqrt{2}}{2}
The square of \sqrt{2} is 2.
\frac{\sqrt{2}}{2}\times \frac{\sqrt{6}}{2}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
\frac{\sqrt{2}\sqrt{6}}{2\times 2}
Multiply \frac{\sqrt{2}}{2} times \frac{\sqrt{6}}{2} by multiplying numerator times numerator and denominator times denominator.
\frac{\sqrt{2}\sqrt{2}\sqrt{3}}{2\times 2}
Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.
\frac{2\sqrt{3}}{2\times 2}
Multiply \sqrt{2} and \sqrt{2} to get 2.
\frac{2\sqrt{3}}{4}
Multiply 2 and 2 to get 4.
\frac{1}{2}\sqrt{3}
Divide 2\sqrt{3} by 4 to get \frac{1}{2}\sqrt{3}.